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How to break up plaintext for RSA?

Given a plaintext of length 20 over the latin alphabet {A, B, . . . , Z} and the
RSA key (n, e) with n = 77. Find a way to break up the plaintext
in as little as possible blocks of information, each of which can be encrypted by
the RSA algorithm using the given key.

My question is,

  1. What are the possibilities for a plaintext (length 20). Is it $26^{20}$ or $26 nPr 20$?

I think, since we have 26 characters we are in the sense writing as 20 characters, then a permutation should be what is needed since we essentially write all possible ways 26 length can be ‘expressed’ into 20 length (permuting).

  1. What is a way to break it up? Taking $log_{77}{P}$ seems like a way. Is there any other way? Even with $log_{77}{P}$, how do I actually proceed to encrypting?

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[PRESS RELEASE – Please Read Disclaimer]

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The post Shamlatech – Metaverse Dev Company Powers Nugen Universe With Exciting Metaverse Solutions appeared first on CryptoPotato.

How to break up plaintext for RSA?

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