CRYPTO NEWS

Wintermute Loses $160 Million to a DeFi Hack

Wintermute, one of the biggest cryptocurrency market makers, recently lost over 160 million dollars to a DeFi hack. The details about the breach have not been released, but it has been confirmed to attack 90 assets. The company’s Chief Executive & Founder, Evgeny Gaevoy, discussed the breach in a string of tweets. Gaevoy confirmed that …

The sum of independent discrete Gaussians is a discrete Gaussian

I am currently learning about lattice-based cryptography and, reading from "A Decade of Lattice Cryptography" by Peikert, specifically section 2.3, it emerges that if the parameter s is greater or equal than the smoothing parameter of a lattice, then the sum of independent discrete gaussians (over that lattice) is a discrete gaussian itself. I am::Listen

I am currently learning about lattice-based cryptography and, reading from "A Decade of Lattice Cryptography" by Peikert, specifically section 2.3, it emerges that if the parameter s is greater or equal than the smoothing parameter of a lattice, then the sum of independent discrete gaussians (over that lattice) is a discrete gaussian itself.

I am looking for the formal statement (and proof) of that fact without any success. Is anyone able to point me to the appropriate reference?

Wintermute Loses $160 Million to a DeFi Hack

Shopping cart
There are no products in the cart!
Continue shopping
0